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Exact volume of the cone =15/4 pi inches^3 approximate value~~11.78 inches^3 to 2 decimal places area of a circle is pir^2 this forms the base of the cone When acid and calcium carbonate are added together in a tube, and the co2 is collected in a tube of limewater, what are all the signs that a chemical has taken place? For a tube the volume would be pir^2xxh where h is height and r is the radius
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A cone is 1/3 the volume of a tube so we have A^2 + b^2 = c^2 substituting the values from the problem gives Volume of a cone =1/3xxpir^2xxh.equation (1) we are given that the diameter is 3 inches
A particle of mass #m# moving with speed #v# hits elastically another stationary particle of mass #2m# inside a smooth horizontal circular tube of radius #r#
The time after which the second collision will happen The tube feet of a starfish are located on its oral surface It is called the oral surface because that is the surface where it's mouth is located, in the center The following video shows the oral surface of a starfish and its tube feet as it moves across the glass of an aquarium.
In a serial dilution, 0.1 ml of serum is added to 1.9 ml of saline in the first tube The next tubes contain 1.5 ml of saline, and 0.5 ml from the previous tube is added to the next tube. What are the differences between a vas deferens and a fallopian tube What is the location of the gene responsible for causing colorblindness
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True species are a) interbreeding b) sharing the same niche c) feeding on same food d) reproductivly isolated? In the given example, the divisor 8 is a power of 2 and 2 is a factor of 10 So the repeating remainder we encounter is actually 0 and the quotient is (normally) identified as a terminating decimal. When combined with metals, it forms compounds with a basic ph
The hydroxide ion combines with alkali metal cations to form basic compounds, such as sodium hydroxide (naoh) When sodium metal is reacted with water, the result is. The volume of the balloon will be 7.8 × 10⁷ L. This is a combined gas law problem: (P_1V_1)/T_1 = (P_2V_2)/T_2 P_1 = 1 atm = 760 mm Hg V_1 = 2.8 × 10⁷ L T_1 = 0.00 °C = 273.15 K P_2 = 243 mm Hg V_2 = ? T_2 = -29.0 °C = 244.2 K (P_1V_1)/T_1 = (P_2V_2)/T_2 V_2 =V_1 × P_1/P_2 × T_2/T_1 = 2.8 × 10^-7 L × (760 mm Hg)/ (243 mm Hg) × (244.2 K)/ (273.15 K) = 7.8 × 10⁷ L Note: The. See a solution process below
